WebApr 6, 2024 · 1 Answer. Sorted by: 0. You just have to factorize A.B + A.B' = A. ( B + B' ). Because ( B + B' ) is always true ( something or not something ), you have A.true and this is purely equivalent to A. AND and OR for factorisation and development works the same has addition and multiplication. This is how you proceed. Web2) XY is parallel to AC. 3) ABC is isosceles. 4) AX ≅CY 15 In triangle ABC below, D is a point on AB and E is a point on AC, such that DE BC. Which statement is always true? 1) ∠ADE and ∠ABC are right angles. 2) ADE ∼ ABC 3) DE = 1 2 BC 4) AD ≅DB 16 In the diagram below, ABC ∼ ADE. Which measurements are justified by this similarity ...
In a right triangle ABC, ∠B = 90°. (a) If AB = 6 cm, BC = 8 cm, find …
WebQuestion: For triangle ABC, we are given that m∠C=28.8∘,AC=26.9 in, and BC=11.5in. We can use the Law of Cosines, Law of Sines, and other properties of triangles to determine all of the missing information. Note that the diagram may not be drawn to scale. Determine all of the missing information about this triangle. a. AB= inches b. WebTriangle ABC ~ Triangle DEF . If AB = 8, BC = 12, AC = 12, and DE = 16, find the perimeter of triangle DEF . Transcribed Image Text: AABC - ADEF. If AB = 8, BC = 12, AC = 12, and DE = 16, find the perimeter of A DEF. Expert Solution Want to see the full answer? Check out a sample Q&A here See Solution star_border inches breakdown
In triangle ABC, C = 135 degrees, A = 15 degrees. If AB = 8 …
WebC. 130 D. 170 11. [14-15 Final Exam #20] In the figure, AGF, AEC and BGED are straight lines. AF and BD bisect BAC and ABC respectively. If AB AC, find CED in terms of a. A. 2a B. 3a C. 2 90 a D. 2 3 135 a 12. [15-16 Final Exam #7] In the figure, AB = AC and BD = CD, BAC = 80° and ABD = 30°. Find BDC. A. 110° B. 120° WebMar 6, 2024 · In \(\triangle \)ABC, ∠B = 90°, AB = 12 cm and AC = 15 cm. D and E are points on AB and AC respectively such that ∠AED = 90° and DE = 3 cm then the area of \(\triangle \)ADE is Q8. If an angle is equal to one-fifth its compliment, then the angle is: WebLet $\frac{A}{2} = \beta$ $10(4\cos^3\beta - 3\cos \beta)= 4\cos \beta$ Since $\cos\beta$ is not equal to zero (if it were equal to zero, then A would be $180^\circ$ and the triangle would not exist), inches bolt size